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y^2-22y-3848=0
a = 1; b = -22; c = -3848;
Δ = b2-4ac
Δ = -222-4·1·(-3848)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{15876}=126$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-126}{2*1}=\frac{-104}{2} =-52 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+126}{2*1}=\frac{148}{2} =74 $
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